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Self Induction

What will be ...

Question

What will be the self inductance of a coil of 100 turns if a current of 5 A produces a magnetic flux $5 \times 10^{- 5}$ Wb?

A

1 mH

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B

10 mH

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C

1

μ

H

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D

10

μ

H

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Solution

The correct option is C 10 $μ$ H
Magnetic field inside the coil= $ϕ = L i$

$⟹ L = \frac{ϕ}{i} = \frac{5 \times 10^{- 5}}{5} H = 10 μ H$ .

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