What will be the volume of $C O_{2}$ at NTP obtained on heating 10 grams of (90% pure) limestone?

22.4 l i t r e s

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20.16 l i t r e s

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2.24 l i t r e s

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2.016 l i t r e s

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Solution

The correct option is D $2.016 l i t r e s$
The given decomposition reaction is,
$C a C O_{3} \to C a O + C O_{2}$

$M a s s o f C a C O_{3} t a k e n i s = \frac{10}{100} \times 90 = 9 g$

Again, $9 g C a C O_{3} = \frac{9}{100} m o l C a C O_{3} = 0.09 m o l C a C O_{3}$

$S o C O_{2} p r o d u c e d = 0.09 \times 22.4 L = 2.016 L$

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