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Question

What would be percentage composition by volume of a mixture of CO and CH_4, whose 10.5 mL requires 9mL oxygen for complete combustion?(1) CO =80% CH_4=20 % (2)CO=90% CH_{4=10%}(4) CO= 66% ,CH_4 =34%(3) CO= 76.2% CH_{4=}23.8%

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