Question

What would you observe in the following case?

Sugar crystal is added to a hard glass test tube containing concentrated sulphuric acid.

Answer 1

1. $\mathrm{conc}.{\mathrm{H}}_2{\mathrm{SO}}_4$ is a dehydrating agent.
2. When sugar crystal is added to $\mathrm{conc}.{\mathrm{H}}_2{\mathrm{SO}}_4$ the atoms of $\mathrm{H}\mathrm{and}\mathrm{O}$ is removed in the ratio $2˸1$ which is the ratio to form a water molecule.
3. The $\mathrm{H}\mathrm{and}\mathrm{O}$ removed in form of steam leaving behind a spongy mass of carbon.
4. $$\begin{gathered} {\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\left(\mathrm{s}\right)\stackrel{\mathrm{conc}.{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }6\mathrm{C}\left(\mathrm{s}\right)+6{\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right) \\ \mathrm{Sugar}\mathrm{Carbon}\mathrm{water} \end{gathered}$$