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Question

When 0.004MNa2SO4 is isotonic with 0.01M solution of glucose at same temperature.the apparent degree of dissociation of sodium sulphate is


A

75%

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B

50%

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C

25%

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D

85%

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Solution

The correct option is A

75%


For Na2SO4,π1=iMRT
=i×0.004×RT
For glucose, π2=CRT
= 0.01 RT
π1=π2 (isotonic)
or 0.004i = 0.01
i = 2.5
Na2SO41Na+SO241001α2αα
Total particles=1α+2α+α
=1+2αi=1+2α1=2.5
α=0.75 or 75% dissociated


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