When 32.25g of ethyl chloride is subjected to de-hydro halogenation reaction, the yield is 50% . The mass of the product formed is (atomic mass of chlorine in 35.5)
7g
C2H5Clalc.KOH−−−−−→−HCl H2C=CH2M.W= M.E=2864.532.25g 14g
If the yield is 50% , 32.25g of ethyl chloride will give 7g of ethylene.