When a solution of specific conductance 1.342Sm−1 was placed in a conductivity cell with parallel electrodes, the resistance was found to be 170.5 ohm. The area of the electrodes is 1.86×10−4 m2 . Calculate the distance between the electrodes.
A
0.0452m
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B
0.425m
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C
4.25m
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D
42.5m
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Solution
The correct option is A0.0452m As per the equation: G=1R (G is conductance ) ……… (1) κ=G×lA ………….. (2)
From 1 and 2 we can also write: κ=1R×lA …………. (3)
Putting the values in equation 3: 1.342=1170.5×l1.86×10−4 ∴l=1.342×170.5×1.86×10−4
On solving we get; l=0.0425m