When a uranium U9223592235U isotope in bombarded with a neutron- it generates Kr36893689Kr- three neutrons and -

nbsp;Nuclear fission reaction of nbsp;U92235_92^235U is, U92235_92^235U +01n→+ _0^1n →Kr3689+_36^89Kr + YZA+_Z^AY + nbsp;30n1+3 _0n^1 + Here, A = 235+ ...

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Standard XII

Physics

Rutherford's Set up and Predictions

When a uraniu...

Question

When a uranium $23592 U$ isotope in bombarded with a neutron, it generates $8936 Kr$ , three neutrons and :

10336 Kr

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10136 Kr

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14456 Ba

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9140 Zr

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Solution

The correct option is C
$14456 Ba$
Nuclear fission reaction of $23592 U$ is,

$23592 U$ $+_{0}^{1} n \to$ $8936 Kr +$ $A Z Y +$ $3_{0} n^{1} +$

Here,

$A = 235 + 1 - 89 - 3 = 144$
$Z = 92 - 36 - 0 = 56$

So that,

$A Z Y =$ $14456 Ba$

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When a uranium 23592U isotope in bombarded with a neutron, it generates 8936Kr, three neutrons and :

The correct option is C 14456Ba Nuclear fission reaction of 23592U is, 23592U +10n→ 8936Kr+ AZY+ 30n1+ Here, A=235+1−89−3=144 Z=92−36−0=56 So that, AZY= 14456Ba

When a uranium $23592 U$ isotope in bombarded with a neutron, it generates $8936 Kr$ , three neutrons and :

The correct option is C
$14456 Ba$
Nuclear fission reaction of $23592 U$ is,

$23592 U$ $+_{0}^{1} n \to$ $8936 Kr +$ $A Z Y +$ $3_{0} n^{1} +$

Here,

$A = 235 + 1 - 89 - 3 = 144$
$Z = 92 - 36 - 0 = 56$

So that,

$A Z Y =$ $14456 Ba$