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Question

When an equimolar mixture of Cu2S and CuS is titrated with Ba(MnO4)2 in acidic medium, the final product contains Cu2+, SO2 and Mn2+. If the molecular weight of Cu2S, CuS and Ba(MnO4)2 are M1, M2 and M3 respectively then:

A
eq. wt. of Cu2S is M18
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B
eq. wt. of CuS is M26
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C
eq. wt. of Ba(MnO4)2 is M35
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D
Cu2S and CuS both have same no. of equivalents in mixture
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Solution

The correct option is B eq. wt. of CuS is M26
+1Cu22SCu+2++4SO2
So, n-factor of Cu2S = 8
Hence, eq. wt. of Cu2S is M18

+2Cu2SCu+2++4SO2
So, n-factor = 6
Hence, eq. wt. of CuS is M26

Ba(+7MnO4)2Mn+2
So, n-factor = 10
eq. wt. of Ba(MnO4)2 is M310

Clearly, as number of moles of CuS and Cu2S is same but n-factor is different. So, equivalents will be different.

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