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Coagulation

When an exces...

Question

When an excess of $A g N O_{3}$ is treated with $K I$ solution, $A g I$ will be produced. $A g I$ will be:

A

Positive charged sol

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B

Negative charged sol

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C

Neutral sol

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D

True solution

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Solution

The correct option is A Positive charged sol
Since $A g N O_{3}$ is in excess, $A g^{+}$ ions in the solution will also be present in excess. This gets absorbed on $A g I$ , thus forming a positive charged sol.

$A g N O_{3} (excess) + K I \to A g I + A g N O_{3} (remaining) - ----------- \to A g I / A g^{+}$

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