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Mole Concept and Avogadro's Number

When Cu2S i...

Question

When $C u_{2} S$ is converted into ${C u}^{2 +}$ and ${S O}_{2}$ , then equivalent weight of ${C u}_{2} S$ will be:
[M = molecular weight of ${C u}_{2} S$ ]

A

M

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B

M/2

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C

M/4

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D

M/8

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Solution

The correct option is D M/8

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Similar questions

Q. The equivalent weight of

{C u}_{2} S

(m o l . w t . = M)

in the following reaction is:

{C u}_{2} S + 4 {M n O}_{4} ⟶ {C u}^{2} + {S O}_{2} + {M n}^{2 +}

Q. The mixture of

C u S

(molar weight =

M_{1}

C u_{2} S

(molecular weight =

M_{2}

) is oxidised by

K M n O_{4}

(molecular weight =

M_{4}

) in acidic medium, the product obtained are

C u^{2 +}

S O_{2 +}

. The equivalent weights of

C u S, C u_{2} S

K M n O_{4}

respectively, are :

Q. When an equimolar mixture of

C u_{2} S

C u S

is titrated with

B a (M n O_{4})_{2}

in acidic medium, the final product contains

C u^{2 +}, S O_{2}

M n^{2 +}

. If the molecular weight of

C u_{2} S, C u S

B a (M n O_{4})_{2}

M_{1}, M_{2}

M_{3}

respectively then,

Q. When an equimolar mixture of

C u_{2} S

C u S

is titrated with

B a (M n O_{4})_{2}

in acidic medium, the final product contains

C u^{2 +}

S O_{2}

M n^{2 +}

. If the molecular weight of

C u_{2} S

C u S

B a (M n O_{4})_{2}

M_{1}

M_{2}

M_{3}

respectively then:

{K M n O}_{4} + {C u}_{2} S ⟶ {M n}^{2 +} + {C u}^{2 +} + {S O}_{2}

In above reaction, find 'n' factor of

{C u}_{2} S

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