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Hydrides of Group 16

When H2O2 i...

Question

When $H_{2} O_{2}$ is added to an acidified solution of $K_{2} C r_{2} O_{7}$ , then :

solution turns green due to formation of

C r_{2} O_{3}

and reduction of

C r

takes place

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solution turns yellow due to formation of

C r O {(O_{2})}_{2}

and no redox change

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a deep blue-violet coloured compound

C r O {(O_{2})}_{2}

due to reduction of

C r

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solution gives green ppt.

C r O {(O_{2})}_{2}

due to oxidation of

C r

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Solution

The correct option is C solution turns yellow due to formation of $C r O {(O_{2})}_{2}$ and no redox change
When $H_{2} O_{2}$ is added to an acidified solution of $K_{2} C r_{2} O_{7}$ , then solution turns yellow due to formation of $C r O {(O_{2})}_{2}$ and no redox change occurs.
The reaction is as follows:
$C r_{2} O_{7}^{2 -} + 2 H^{+} + 4 H_{2} O_{2} ⟶ 2 C r O {(O_{2})}_{2} + 5 H_{2} O$

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