Question

When $H_{2}S$ gas is passed into $S{O}_2$ in aqueous solution, colloidal yellowish white turbidity appears.

Calculate the weight of this turbidity if $11.2L$ of each gas reacts at $NTP$.

• A. $3\text{mol}$
• B. $\frac{3}{4}\text{mol}$
• C. $\frac{3}{2}\text{mol}$
• D. $\frac{1}{2}\text{mol}$

Answer 1

The correct option is B $\frac{3}{4}\text{mol}$

$\begin{array}{ccccccc}S{O}_2& +& 2H_{2}S& ⟶& 2H_{2}O& +& 3S\\ 1mol& & 2mol& & & & \text{3 mol (colloidal trubidity)}\\ \frac{1}{2}mol& & \frac{1}{2}mol& & & & \frac{3}{4}mol=24g\\ & & & & & & \text{(11.2 L of each at NTP =}\frac{1}{2}mol\text{)}\end{array}{H}_{2}S\text{is limiting reactant, hence S formed =}\frac{3}{4}\text{mol}$