When limestone is heated- quicklime is formed according to the equation- CaCO 3 s - CaO s - CO 2 g The experiment was carried out in the temperature range 800-900- C- Equilibrium constant K p follows the relation- log K p -7-282-8500- T where- T is temperature in Kelvin- At what temperature the decomposition will give CO 2 g at 1 atm - A- 894-11- CB- 794-66- CC- 987-18- CD- 635-45- C

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Standard XII

Chemistry

Derivation of Kp and Kc

When limeston...

Question

When limestone is heated, quicklime is formed according to the equation.
$C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$
The experiment was carried out in the temperature range $800 - 900^{o} C,$ Equilibrium constant $K_{p}$ follows the relation. $l o g K_{p} = 7.282 - \frac{8500}{T}$
where, T is temperature in Kelvin. At what temperature the decomposition will give $C O_{2} (g)$ at 1 atm?

{894.11}^{o} C

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{794.66}^{o} C

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{635.45}^{o} C

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{987.18}^{o} C

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Solution

The correct option is A ${894.11}^{o} C$
The given equation for decompositon of Quicklime $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$
The experiment was carried out in the temperature range $800 - 900^{o} C .$ Equilibrium constant $K_{p}$ follows the relation,
$l o g K_{p} = 7.282 - \frac{8500}{T}$
where, T is temperature in Kelvin.

The decomposition gives $C O_{2} (g)$ at 1 atm
$K_{p} = P_{C O_{2}} = 1$
$l o g K_{p} = 7.282 - \frac{8500}{T}$
$l o g 1 = 7.282 - \frac{8500}{T}$
$0 = 7.282 - \frac{8500}{T}$
$7.282 = \frac{8500}{T}$
$T = {1167.26}^{o} C$
$T = 1167.26 - {273.15}^{o} C = {894.11}^{o} C$
The temperature is ${894.11}^{o} C$

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Similar questions

Q. When limestone is heated, quicklime is formed according to the equation.

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)

The experiment was carried out in the temperature range

800 - 900^{o} C,

Equilibrium constant

K_{p}

follows the relation.

l o g K_{p} = 7.282 - \frac{8500}{T}

where, T is temperature in Kelvin. At what temperature the decomposition will give

C O_{2} (g)

at 1 atm?

Q. When limestone is heated, quicklime is formed according to the equation,

C a {C O}_{3} (s) ⇌ C a O (s) + C O_{2} (s)

The experiment was carried out in the temperature range

{800 - 900}^{o} C

. Equilibrium constant

K_{p}

follows the relation,

log K_{p} = 7.282 - 8500 / T

where,

T

is temperature in Kelvin. At what temperature the decomposition will give

{C O}_{2} (g)

1

atm?

Q. In the preparation of quick lime from limestone, the reaction is:

C a C O_{3 (s)} ⇌ C a O_{(s)} + C O_{2 (g)}

Experiments carried out between

850^{\circ} C

and

950^{\circ} C

led to a set of

K_{p}

values fitting in empirical equation

l n K_{p} = 7.282 - \frac{8500}{T}

, where

T

is the absolute temperature. If the reaction is carried out in quiet air, what minimum temperature would be predicted from this equation for almost complete decomposition of lime?

Q. In the preparation of

C a O

from

C a {C O}_{3}

using the equilibrium

C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g)

K_{p}

is expressed as

log K_{p} = 7.282 - \frac{8500}{T}

for the complete decomposition of

{C a C O}_{3}

, the temperature in celsius to be used is____________.

In the preparation of

C a O

from

C a {C O}_{3}

using the equilibrium

C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g)

K_{p}

is expressed as:

log K_{p} = 7.282 - \frac{8500}{T}

for complete decomposition of

C a {C O}_{3}

the temperature in celsius to be used is:

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Derivation of Kp and Kc

Standard XII Chemistry

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