Question

When $NaCl$ is doped with $1.0\times {10}^{-3}$ mole of $SrC{l}_2$, the number of cation vacancy is ?

• A. $6.023\times {10}^{18}$
• B. $6.023\times {10}^{20}$
• C. $2\times 6.023\times {10}^{20}$
• D. $3.011\times {10}^{20}$

Answer 1

The correct option is B

$6.023\times {10}^{20}$

Two $N{a}^{+}$ ions are replaced by one $S{r}^{2+}$ ions doped $=1.0\times {10}^{-3}\times 6.02\times {10}^{23}=6.02\times {10}^{20}$