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Oxidising Reagent and Reducing Reagent

When oxalic a...

Question

When oxalic acid reacts with conc. $H_{2} S O_{4}$ , two gases produced are neutral and acidic in nature respectively. Potassium hydroxide absorbs one of the two gases. The product formed during this absorption and the gas which gets absorbed are respectively:

K_{2} C O_{3}

and

C O_{2}

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K H C O_{3}

and

C O_{2}

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K_{2} C O_{3}

and

C O

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K H C O_{3}

and

C O

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Solution

The correct option is A $K_{2} C O_{3}$ and $C O_{2}$
$(C O O H)_{2} c o n c . H_{2} S O_{4}, h e a t - --------- \to C O + C O_{2} + H_{2} O$
$C O$ is neutral and $C O_{2}$ is acidic in nature.
$2 K O H + C O_{2} \to K_{2} C O_{3} + H_{2} O$

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Similar questions

C O_{2}

C O_{2}

K_{2} C O_{3}

C O_{2}

10 g

K H C O_{3}

6.31 g

K_{2} C O_{3}

1.07 g

H_{2} O

C O_{2}

10 g

K H C O_{3}

6.31 g

K_{2} C O_{3}

1.07 g

H_{2} O

C O_{2}

H_{2} S O_{4}

K O H

N a H C O_{3},

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