When strongly heated, orthoboric acid leaves a residue of:

Metaboric acid

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Tetraboric acid

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Boric anhydride

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Boron

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Solution

The correct option is C
Boric anhydride

$H_{3} B O_{3}$ $100^{o} C - -- \to$ $H B O_{2}$ + $H_{2} O$

$H B O_{2}$ $160^{o} C - -- \to$ $H_{2} B_{4} O_{7}$ + $H_{2} O$

$H_{2} B_{4} O_{7}$ $△ - \to$ 2 $B_{2} O_{3}$ + $H_{2} O$

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Similar questions

When orthoboric acid is heated to red heat the residue is

(H_{3} B O_{3})

(H_{3} B O_{3})

(H_{3} B O_{3})

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