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Question

When the load on a wire is slowly increased from 3 to 5 kg, the elongation increases from 0.61 to 1.02 mm. The work done during the extension of wire is

A
0.16 J
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B
0.016 J
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C
1.6 J
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D
16 J
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Solution

The correct option is B 0.016 J

Work done in stretching a wire is given by
W = 12 × stretching force × extension.

Net work done in increasing the length from 0.61 mm to 1.02 mm is
W2W1
here
W2 is workdone in stretching wire to 1.02 mm at aload of 5 kg
W1 is workdone in stretching wire to 0.61 mm at aload of 3 kg

W2W1=12×5×9.8×1.02×10312×3×9.8×0.61×103=0.016 J


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