When the load on a wire is slowly increased from 3 to 5 kg wt, the elongation increases from 0.61 to 1.02 mm. The work done during the extension of wire is

Q. When the load on a wire is slowly increased from

3

5 k g

, the elongation increases from

0.61

1.02 m m

. The work done during the extension of wire is

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When the load on a wire is slowly increased from 3 to 5 kg−wt, the elongation increases from 0.61 mm to 1.02 mm. The work done during the extension of wire is

The correct option is B 0.016 JWork done = F×Δl2 Wi=3×9.81×0.61×10−32 Wf=5×9.81×1.02×10−32 ΔW=Wf−Wi=0.016 J

When the load on a wire is slowly increased from 3 to 5 $k g - w t$ , the elongation increases from $0.61 m m$ to $1.02 m m$ . The work done during the extension of wire is

The correct option is B $0.016 J$
Work done = $\frac{F \times Δ l}{2}$
$W_{i} = \frac{3 \times 9.81 \times 0.61 \times 10^{- 3}}{2}$
$W_{f} = \frac{5 \times 9.81 \times 1.02 \times 10^{- 3}}{2}$
$Δ W = W_{f} - W_{i} = 0.016 J$