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Zinc II Oxide

When the same...

Question

When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is $X : Y$ . Find the value of $\frac{X}{Y}$ .

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Solution

$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$
$Z n + 2 N a O H \to N a_{2} Z n O_{2} H_{2}$
The ratio of volumes of $H_{2}$ evolved in both the cases is $1 : 1.$ Hence , $\frac{1}{1} = 1$ .

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