When two capillary tubes A and B are immersed in water, the heights of water columns are found to be in the ratio 2:3. The ratio of the radii of tubes A and B is:

2 : 3

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4 : 9

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9 : 4

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3 : 2

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Solution

The correct option is D 3 : 2
$h \propto \frac{1}{r}$
$h_{1} r_{1} = h_{2} r_{2}$
$\frac{2}{3} r_{1} = r_{2} \Rightarrow \frac{r_{1}}{r_{2}} = 3 / 2$

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When two capillary tubes A and B are immersed in water, the heights of water columns are found to be in the ratio 2:3. The ratio of the radii of tubes A and B is:

The correct option is D 3 : 2h∝1rh1r1=h2r223r1=r2⇒r1r2=3/2

The correct option is D 3 : 2
$h \propto \frac{1}{r}$
$h_{1} r_{1} = h_{2} r_{2}$
$\frac{2}{3} r_{1} = r_{2} \Rightarrow \frac{r_{1}}{r_{2}} = 3 / 2$