When two liquid of same mass but different densities, $p_{1} a n d p_{2}$ are mixed together, then the density of the mixture is

p_{1} + p_{2}

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\frac{p_{1} + p_{2}}{2}

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\frac{{2 p}_{1} p_{2}}{p_{1} + p_{2}}

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{2 p}_{1} + {2 p}_{2}

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Solution

The correct option is B $\frac{{2 p}_{1} p_{2}}{p_{1} + p_{2}}$
we know that mass= volume x density
According to question:
$m = v_{1} ρ_{1} = v_{2} ρ 2$

new volume $v = v_{1} + v_{2}$

$\frac{2 m}{ρ} = \frac{m}{ρ_{1}} + \frac{m}{ρ_{2}}$

$ρ = \frac{2 ρ_{1} ρ_{2}}{ρ_{1} + ρ_{2}}$

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When two liquid of same mass but different densities, p1 and p2 are mixed together, then the density of the mixture is

The correct option is B 2p1p2p1+p2we know that mass= volume x densityAccording to question:m=v1ρ1=v2ρ2new volume v=v1+v22mρ=mρ1+mρ2ρ=2ρ1ρ2ρ1+ρ2

When two liquid of same mass but different densities, $p_{1} a n d p_{2}$ are mixed together, then the density of the mixture is

The correct option is B $\frac{{2 p}_{1} p_{2}}{p_{1} + p_{2}}$
we know that mass= volume x density
According to question:
$m = v_{1} ρ_{1} = v_{2} ρ 2$

new volume $v = v_{1} + v_{2}$

$\frac{2 m}{ρ} = \frac{m}{ρ_{1}} + \frac{m}{ρ_{2}}$

$ρ = \frac{2 ρ_{1} ρ_{2}}{ρ_{1} + ρ_{2}}$