Question

Which carbon atom will show minimum electronegativity -

H ${}^{1}C$ $\equiv$ ${}^{2}C$ - C${}^{3}H$ - C${}^{4}H$ - C${}^{5}H$

• A. Fifth
• B. Third
• C. First
• D. Second

Answer 1

The correct option is A

Fifth

${sp}^3$ - hybridised carbon has 25% s character , 75% p character.

${sp}^2$ $\to$ 33.3% s character, 66.6% p character

sp $\to$ 50% s and 50% p

More the s character, more is the electronegativity.

H $C^1$ $\equiv$ $C^2$ - $C^{3}H$ =$C^{4}H$ - $C^5{H}_3$

1 & 2 $\to$ sp

$5^{th}$ carbon is ${sp}^3$

3 & 4 $\to$ ${sp}^2$