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Question

Which is/are not correct variation of indicated properties in NH−2,NH3 and NH+4

A
NH2<NH3<NH+4,(HNH) bond angle
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B
NH2<NH3<NH+4 lone pairs on N - atom
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C
NH2<NH3<NH+4(NH) bond length
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D
NH2<NH3<NH+4 number of s and p - orbitals used in hybridisation
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Solution

The correct option is D NH2<NH3<NH+4 number of s and p - orbitals used in hybridisation
a) Bond angle is maximum in NH+4 due to absence of any lone pair. So, (a) is correct.

b) Number of lone pair maximum in NH2 thus (b) is incorrect.

c) As the number of lone pair increases, p-character in the NH bond increases and hence NH bond length increases. Hence the correct order of bond length,
NH2>NH3>NH+4(NH) bond length
hence c is incorrect.


d)All the three species are sp3 hybridized and hence d is incorrect

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