Which is the lowest number that should be subtracted from $153$ so that the digits in the tens and ones places of the resulting number are the same?
(Hint: Look for the number nearest to $153$ with the same digit in tens and ones places.)

7

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Solution

The correct option is B $9$
Say:
We have to subtract the least number from $153$ that has the same digits in tens and ones places.
The nearest number that has the same digits in tens and ones places are $144$ and $155.$
As we need to subtract from $153,$ the number that we can choose here will be $144.$
Let us now find the answer by subtracting these two numbers.
Step:
$153 = 100 + 50 + 3$
$144 = 100 + 40 + 4$
So, $153 - 144 = 9$
Hence, $9$ needs to be subtracted from $153$ to arrive at a number that has the same digit in tens and ones place.
So, option C is the correct answer.

Probing Q: Is there any other way to find this out?

A: We can count forward from $144$ to $153$ to find the answer.

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Which is the lowest number that should be subtracted from 153 so that the digits in the tens and ones places of the resulting number are the same? (Hint: Look for the number nearest to 153 with the same digit in tens and ones places.)

Which is the lowest number that should be subtracted from $153$ so that the digits in the tens and ones places of the resulting number are the same?
(Hint: Look for the number nearest to $153$ with the same digit in tens and ones places.)