The correct option is D All of the above
In solution,
HOAc→OAc−+H+
H2O→H++OH−
in solution, total positive charge from all species equal to total negative charge from all species so
[H+]eq.=[OAc−]eq.+[OH−]eq..
Also, analytical concentration of a species is equal to the sum of the equillbrium concentration of all its species
[HOAc]=[HOAcc]eq.+[OAc−]eq.=0.10M
and in acidic solution,
[H+]>[OH−]