Which of the following has maximum number of molecules

16 gm of

O_{2}

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16 gm of

N O_{2}

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7 gm of

N_{2}

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2 gm of

H_{2}

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Solution

The correct option is C 2 gm of $H_{2}$
$No. of moles of 7g N_{2} = 7 / 28 = 1 / 4;$
$No. of moles of 2g H_{2} = 2 / 2 = 1;$
$No. of moles of 16g N O_{2} = 16 / 46 = 8 / 23 = 1 / 3;$
$No. of moles of 16g O_{2} = 16 / 32 = 1 / 2$
$H e r e, n_{H_{2}} > n_{O_{2}} > n_{N O_{2}} > n_{N_{2}}$

$Since, more the no. of moles more will be the no. of molecules.$
$Thus 2g H_{2} has the maximum no. of molecules.$

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Similar questions

A gaseous mixture contain 1 gm of $H_{2},$ 4 gm of $H e$ 7gm of $N_{2}$ and 8gm of $O_{2}$ . The gas having the highest partial pressure is:

16 gm of $O_{2}$ gas and x gm of $H_{2}$ gas occupy the same volume at the same temperature and pressure. Then x is :

16

O^{2 -}

4.0

H_{2}

56.0

N_{2}

H_{2}

N_{2}

H_{2}

O_{2}

27^{\circ} C

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