Which of the following ion has the maximum value of magnetic moment?

M n^{2 +}

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F e^{2 +}

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C o^{2 +}

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N i^{2 +}

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Solution

The correct option is A $M n^{2 +}$
Magnetic moment of an ion is given as : $\sqrt{n (n + 2)} B M$
Where, n=number of unpaired electrons. More is the number of unpaired electrons,higher will be the magnetic moment.
(a) $M n^{2 +} = 3 d^{5} 4 s^{0}$
Number of unpaired electrons =5
(b) $F e^{2 +} = 3 d^{6} 4 s^{0}$
Number of unpaired electrons = 4
(c) $C o^{2 +} = 3 d^{7} 4 s^{0}$
Number of unpaired electrons = 3
(d) $N i^{2 +} = 3 d^{8} 4 s^{0}$
Number of unpaired electrons = 2.
As maximum number of unpaired electron is in $M n^{2 +}$ . Hence, $M n^{2 +}$ will have highest magnetic moment among all.

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