Which of the following is correct order of acidic strength?

$H C l O_{4} > H_{2} S O_{4} > H_{3} P O_{4}$

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$H C l O_{4} > H_{3} P O_{4} > H_{2} S O_{4}$

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$H_{2} S O_{4} > H C l O_{4} > H_{3} P O_{4}$

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$H_{2} S O_{4} > H_{3} P O_{4} > H C l O_{4}$

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Solution

The correct option is A
$H C l O_{4} > H_{2} S O_{4} > H_{3} P O_{4}$

The greater the electronegativity of the central atom, the higher the acidic strength! This is because of the general ability of the more-electronegative central atom to stabilize the conjugate base after the acid molecule loses its proton.

Suggest Corrections

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H_{3} P O_{4}

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y

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H_{2} C O_{3}, H_{3} P O_{3}, C H_{3} C O O H, H_{2} S O_{4}, H_{3} P O_{2}, H_{4} P_{2} O_{7}, H C l O_{4}, H_{3} B O_{3}, H N O_{3} .

H O C l, H C l O_{2}, H C l O_{3}

H C l O_{4}

H_{2} S O_{4}

H C l O_{4}

H_{2} S O_{4}

H C l O_{4}

H C l O

H C l O_{4}

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