Which of the following is diamagnetic ion?

Z n^{2 +}

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N i^{2 +}

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C o^{2 +}

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C u^{2 +}

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Solution

The correct option is A $Z n^{2 +}$
${Z n}^{2 +} \equiv [N e] {3 s}^{2} {3 p}^{6} {4 s}^{0} {3 d}^{10}$
It is diamagnetic, so no unpaired $e^{-} s$ .

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Similar questions

Z n^{2 +}, N i^{2 +}, C u^{2 +} and C r^{2 +}

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

C u^{2 +}, N i^{2 +}, C o^{2 +}, F e^{2 +}

M n^{2 +}

Consider the following reaction which of the following statement is true for this cell reaction.

(Zn + Cu²⁺ → Zn²⁺ + Cu)

F e^{2 +}, N i^{2 +}, C a^{2 +}, K^{+}, M g^{2 +}, N a^{+}, C u^{2 +}, Z n^{2 +}

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