Which of the following is not formed when $H_{2} S$ reacts with acidic $K_{2} C r_{2} O_{7}$ solutions?

K_{2} S O_{4}

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C r_{2} (S O_{4})_{3}

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S

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C r S O_{4}

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Solution

The correct option is D $C r S O_{4}$
$K_{2} C r_{2} O_{7} + H_{2} S \to C r_{2} (S O_{4})_{3} + S + K_{2} S O_{4} + H_{2} O$

The oxidation number of chromium changes from +6 to +3, not to 2! so $C r S O_{4}$ cannot be formed.

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