Which of the following is not formed when $H_{2} S$ reacts with acidic $K_{2} C r_{2} O_{7}$ solution?

C r S O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C r_{2} (S O_{4})_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C r S O_{4}$

$3 H_{2} S + K_{2} C r_{2} O_{7} + 4 H_{2} S O_{4} \to 3 S + C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + 7 H_{2} O$

Hydrogen sulfide react with acidic ( $H_{2} S O_{4}$ ) potassium dichromate to produce sulfur, chromium(III) sulphate ( $C r_{2} (S O_{4})_{3}$ ), potassium sulphate ( $K_{2} S O_{4}$ ) and water.
Hence option $A$ is correct.

Suggest Corrections

Similar questions

H_{2} S

K_{2} C r_{2} O_{7}

H_{2} S

K_{2} C r_{2} O_{7}

H_{2} S

M n O_{4}^{-}

K M n O_{4}

H_{2} O_{2}

K_{2} C r_{2} O_{7}

H_{2} S

Join BYJU'S Learning Program