Which of the following is the industrial method of preparation of acetaldehyde?

C H_{3} C N S n C l_{2} - -- \to H C l C H_{2} C H = N H H_{3} O^{+} - -- \to C H_{3} C H O

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C H_{3} C O C l + H_{2} P d - -- \to B a S O_{4} C H_{3} C H O + H C l

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C H_{2} = C H_{2} + H_{2} O P d^{2 +} - -- \to C H_{3} C H O

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All of the above

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Solution

The correct option is A $C H_{2} = C H_{2} + H_{2} O P d^{2 +} - -- \to C H_{3} C H O$
The industrial method of production of acetaldehyde is the oxidation of ethylene by the Wacker process, which involves oxidation of ethylene using a homogeneous palladium/copper system. Hence, C is the correct answer.

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Similar questions

(1) C H_{3} C H = C H_{2} + H B R - ---------- \to C H_{3} C H_{2} C H_{2} - B r

(2) C H_{3} C H = C H_{2} + C I_{2} - --------- \to C H_{3} C H (C l) C H_{3}

(3) C H_{3} C H = C H_{2} + H C I - ---------- \to C l - C H_{2} C H = C H_{2}

(4) C H_{3} C H_{3} + C l_{2} h r - \to C I - C H_{2} C H = C H_{2}

{[\begin{matrix} - C H_{2} - C H ∣ O H - C H_{2} - C H ∣ O H - C H_{2} - C H ∣ O H - \end{matrix}]}_{n}

C H_{2} = C H_{2} + C H_{3} C O C l A l C l_{3} - -- \to

C H_{2} = C H - C H_{2} C l + R M g X \to

{C H}_{2} = {C H}_{2} + {B r}_{2} N a C l - -- \to P r o d u c t s

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