Question

Which of the following molecules is both planer and linear

• A. $C{H}_2=CH-CH=C{H}_2$
• B. $CH\equiv C-C\equiv CH$
• C. $C{H}_3-C\equiv C-C\equiv C-C{H}_3$
• D. $C{H}_2=C=C{H}_2$

Answer 1

The correct option is A $C{H}_2=CH-CH=C{H}_2$

There are three types of Hybridization-

$sp$=Linear, When Carbon is bonded to other Carbon with a triple bond.

$s{p}^2$= planer-When Carbon is bonded to other Carbon with a double bond.

$s{p}^3$= tetrahedral-When Carbon is bonded to other Carbon with a single bond

In option A following are hybridization:

$C^1{H}_2=C^{2}H-C^{3}H=C^4{H}_2$

Here $C^1$ and $C^4$ are planer with $s{p}^2$

$C^2$ and $C^3$ are linear with $sp$

Option A is the correct answer