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Standard X

Chemistry

Ionic Salts and Their Characteristic

Which of the ...

Question

Which of the following pairs are good oxidizing agent?

B r_{2}

and

H g

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C l_{2}

and

F_{2}

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N H_{4}^{+}

and

H_{3} O^{+}

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F e

and

C o

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Diamond and graphite

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Solution

The correct option is B $C l_{2}$ and $F_{2}$
$C l_{2}$ and $F_{2}$ are good oxidizing agents.
$C l_{2}$ and $F_{2}$ are highly electronegative elements.
They have high tendency to accept electrons.
Hence, they themselves are reduced and oxidizes other substances.

Suggest Corrections

Similar questions

Q. Consider the following orders –
(1)

F_{2} > C l_{2} > B r_{2} > I_{2} :

boiling point
(2)

F_{2} > C l_{2} > B r_{2} > I_{2} :

oxidizing nature
(3)

F_{2} > C l_{2} > B r_{2} > I_{2} :

EN
(4)

F_{2} > C l_{2} > B r_{2} > I_{2} :

BDE
(5)

F_{2} > C l_{2} > B r_{2} > I_{2} :

EA
(6)

F_{2} > C l_{2} > B r_{2} > I_{2} :

Reactivity
(7)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Acidic nature
(8)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Oxidizing nature
Then calculate

(x^{2} + y^{2})

when

x

is correct order and

y

is incorrect order.

Q. The electron affinity values

(i n k J m o l^{- 1})

of three halogens x, y and z are respectively -349, -333 and -325. Then x, y and z are respectively

Q. Diamond and graphite are good conductors of electricity.

Q. Which of the following options does not give to the correct trends indicated against it?
(I)

F_{2} > C l_{2} > B r_{2} > I_{2}

: Bond dissociation energy
(II)

F_{2} > C l_{2} > B r_{2} > I_{2}

: Oxidizing nature
(III)

C l > F > B r > I

: Electron gain enthalpy
(IV)

F > C l > B r > I

: Electronegativity

Q. Bond energy of

F_{2}, C l_{2}

and

B r_{2}

follow the order:

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Which of the following pairs are good oxidizing agent?

The correct option is B Cl2 and F2Cl2 and F2 are good oxidizing agents.Cl2 and F2 are highly electronegative elements. They have high tendency to accept electrons.Hence, they themselves are reduced and oxidizes other substances.

The correct option is B $C l_{2}$ and $F_{2}$
$C l_{2}$ and $F_{2}$ are good oxidizing agents.
$C l_{2}$ and $F_{2}$ are highly electronegative elements.
They have high tendency to accept electrons.
Hence, they themselves are reduced and oxidizes other substances.