Which of the following reactions is/are correct when $C l_{2}$ reacts with $N H_{3}$ ?

N H_{3} + C l_{2} \to N C l_{3} + H C l

E x c e s s

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N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

E x c e s s

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N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

E x c e s s

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N H_{3} + C l_{2} \to N C l_{3} + H C l

E x c e s s

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Solution

The correct option is D $N H_{3} + C l_{2} \to N C l_{3} + H C l$
$E x c e s s$
$N H_{3} (e x c e s s) + C l_{2} \to N_{2} + N H_{4} C l$

$N H_{3} + C l_{2} (e x c e s s) \to N C l_{3} + H C l$

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