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C
CH3−COOHNaOH/HOH−−−−−−−−→
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D
All of these
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Solution
The correct option is ACH3−CHO(i)NaCN/HCl−−−−−−−−−→(ii)H2O/H⊕/Δ Treatment of acetaldehyde with sodium cyanide in presence of HCl gives acetaldhyde cyanohydrin. This is followed by hydrolysis of cyano group in presence of acid to form hydroxy acid as a product which is 2-hydroxy propanoic acid.