Which of the following samples will have the same number of atoms as 40 g calcium?

24 g magnesium

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64 g silphur

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14 g nitrogen

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8 g oxygen

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Solution

The correct option is A 24 g magnesium
Molar mass of $C a = M ‘ = 40$
Molar mass of $M g = M = 24$
Given mass of $C a = m ‘ = 40 g$
Given mass of $M g = m = ?$

Formula: $m = m ‘ \times M / M ‘$

$m = 40 \times \frac{24}{40}$

$m = 24 g$

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In a compound of magnesium (Mg = 24) and nitrogen (N= 14 ), 18 g of magnesium combines with 7 g of nitrogen.
Deduce the simplest formula by answering the following questions:
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Which of the following samples will have the same number of atoms as 40 g calcium?

The correct option is A 24 g magnesiumMolar mass of Ca=M‘=40Molar mass ofMg=M=24Given mass of Ca=m‘=40gGiven mass of Mg=m=? Formula: m=m‘×M/M‘ m=40×2440 m=24g

The correct option is A 24 g magnesium
Molar mass of $C a = M ‘ = 40$
Molar mass of $M g = M = 24$
Given mass of $C a = m ‘ = 40 g$
Given mass of $M g = m = ?$

Formula: $m = m ‘ \times M / M ‘$

$m = 40 \times \frac{24}{40}$

$m = 24 g$