The correct option is C The vapour will contain a higher percentage of benzene.
pbenzene=xbenzeneP0benzene
ptoluene=xtoluene P0toluene
For an ideal 1 : 1 molar mixture of benzene and
tolune, xbenzene=12 and xtoluene=12
pbenzene=12 P0benzene=12×12.8KPa=6.4 kPa
ptolune=12P0toluene=12×3.85 KPa=6.4 kPa
Thus, the vapour will contain a high percentage of benzene as the partial vapour pressure of benzene is higher as compared to that of toluene.