Which of the following will have the maximum dipole moment?

C H_{3} F

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C H_{3} C l

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C H_{3} B r

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C H_{3} I

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Solution

The correct option is D $C H_{3} C l$
The dipole moment of $C H_{3} C l$ is the highest, as the dipole moment depends on the electronegativity of halogens and $F$ has the highest among $C l, B r$ and $I$ .

But due to less distance between $F$ and $C$ of $C H_{3} F$ , its dipole moment decreases.

The order of the dipole moment is $C H_{3} C l > C H_{3} F > C H_{3} B r > C H_{3} I$ .

Hence, the correct option is $B$

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Similar questions

Compare the dipole moment of the following.

CH₃F,CH₃Cl,CH₃Br, CH3 I.

C H_{3} C l

C H_{3} F

C H_{3} C l, C H_{3} B r, C H_{3} I

C H_{3} F

C H_{3} C l, C H_{3} B r, C H_{3} I, C H_{3} F

Which has highest bond dissociation energy?

CH3F. CH3Cl . CH3Br. CH3I

PLS EXPLAIIN IN DETAIL ans is ch3F

MY opinion ch3I coz in ch3F F is more electronegativity so it has pulled electrons therefore it is easier to break the bond

And CH3I. I will nt attract electron compared to F

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