Which of these is the formula for fining maximum horizontal range of a projectile given its initial velocity and angle of projection?

\frac{u^{2} s i n 2 θ}{g}

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\frac{u^{2} s i n 2 θ}{2 g}

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\frac{2 u^{2} s i n 2 θ}{g}

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\frac{2 u s i n 2 θ}{g}

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Solution

The correct option is A $\frac{u^{2} s i n 2 θ}{g}$

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The velocity at the maximum height of a projectile is half of its initial velocity of projection u. Its range on the horizontal plane is

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