Which one is the correct order of acidity ?

C H_{2} = C H_{2} > C H_{3} - C H = C H_{2} > C H_{3} - C \equiv C H > C H \equiv C H

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C H \equiv C H > C H_{3} - C \equiv C H > C H_{2} = C H_{2} > C H_{3} - C H_{3}

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C H \equiv C H > C H_{2} = C H_{2} > C H_{3} - C \equiv C H > C H_{3} - C H_{3}

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C H_{3} - C H_{3} > C H_{2} = C H_{2} > C H_{3} - C = C H > C H \equiv C H

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Solution

The correct option is B $C H \equiv C H > C H_{3} - C \equiv C H > C H_{2} = C H_{2} > C H_{3} - C H_{3}$
Alkynes having $s p$ - hybridised carbon has maximum $s$ - character and hence maximum electronegativity so that it attracts the electron pair of the bond $C - H$ to a greater extent and makes the removal of proton easier than the alkenes having $s p^{2}$ hybridised carbon.
$s p^{3}$ hybridised carbon is less electronegative than $s p^{2}$ .

Hence, the correct order is
$C H \equiv C H 2- acidic hydrogen > C H_{3} - C \equiv C H 1- acidic hydrogen > C H_{2} = C H_{2} > C H_{3} - C H_{3}$

Thus, option (b) is correct.

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