Question

Which one is the Swartz reaction from the following?

• A. $C{H}_{3}Cl+NaI\stackrel{\text{Dry Acetone}}{⟶}C{H}_{3}I+NaCl$
• B. $C{H}_{3}Br+NaI\stackrel{\text{Dry Acetone}}{⟶}C{H}_{3}I+NaBr$
• C. $C{H}_{3}Br+AgF⟶C{H}_{3}F+AgBr$
• D. $2C{H}_{3}Cl+2Na\stackrel{\text{Dry ether}}{⟶}C{H}_3-C{H}_3+2Na$

Answer 1

The correct option is C $C{H}_{3}Br+AgF⟶C{H}_{3}F+AgBr$

Alkyl fluorides are prepared by the action of heavy metallic (mercurous or antimony) fluorides on corresponding alkyl chloride or bromide and is called Swartz reaction.
$C{H}_{3}Br+AgF\to C{H}_{3}F+AgBr$
Reaction (a) and (b) is Finkelstein reaction.
Reaaction (d) is Wurtz reaction.
Thus, option (c) is correct.