Which one is the Swartz reaction from the following?

C H_{3} C l + N a I Dry Acetone ⟶ C H_{3} I + N a C l

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C H_{3} B r + N a I Dry Acetone ⟶ C H_{3} I + N a B r

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C H_{3} B r + A g F ⟶ C H_{3} F + A g B r

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2 C H_{3} C l + 2 N a Dry ether ⟶ C H_{3} - C H_{3} + 2 N a

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Solution

The correct option is C $C H_{3} B r + A g F ⟶ C H_{3} F + A g B r$
Alkyl fluorides are prepared by the action of heavy metallic (mercurous or antimony) fluorides on corresponding alkyl chloride or bromide and is called Swartz reaction.
$C H_{3} B r + A g F \to C H_{3} F + A g B r$
Reaction (a) and (b) is Finkelstein reaction.
Reaaction (d) is Wurtz reaction.
Thus, option (c) is correct.

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C H_{3} B r + A g F \to C H_{3} F + A g B r

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