The correct option is
C Hinsberg'st test is used to distinguish between primary, secondary and tertiary amines.
Tertiary amines does not react with Benzyl sulphonyl chloride to form sulphonamides.
Reaction (b) is stephen reaction.
CN is reduced to iminium salt followed by hydrolysis to give aldehyde group.
Sodium in alcohol is a strong reducing agent and reduces nitriles to amines.
LiAlH4 will reduce nitrile to amide and followed by hydrolysis to give primary amine.
CN is reduced to amines in presence of
H2/Ni.
Thus, rest of the reactions (a), (c) and (d) give amine group containing product. So, they can react with Hinsberg reagent
Hence, option (b) is correct.