Which reaction below demonstrates the lewis definition of acids and bases?

H C l + N a O H \to H O H + N a C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} O + N H_{3} \to O H^{-} + N H_{4}^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N H_{3} + B F_{3} \to N H_{3} B F_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H I + K O H \to H_{2} O + K I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H^{+} O H^{-} \to H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $N H_{3} + B F_{3} \to N H_{3} B F_{3}$
Lewis acid: Lone pair acceptor

Lewis base: Lone pair donor

So, ${N H}_{3} + {B F}_{3} \to H_{3} N :\to B F_{3}$
L. base L. acid

Hence, the correct option is C.

Suggest Corrections

Similar questions

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

H_{2} O + N_{3} \to O H^{-} + N H_{4}^{-}

H S^{-} + H C l \to C l^{-} + H_{2} S

H S^{-} + N H_{3} \to N H_{4}^{+} + S^{2 -}

H C l + N a O H \to N a C l + H_{2} O

N a C l + H_{2} O \to H C l + N a O H

N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-} i s :

N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-}

N H_{3} + H_{2} O ⇌ N H_{4}^{+} + O H^{-}

H_{2} O + N H_{3} \to N H_{4}^{+} + O H^{-}

Join BYJU'S Learning Program