Question

Which reagent (A) is used for the following given conversion?

• A. $\mathrm{Cu}/∆/$high pressure
• B. Molybdenum Oxide
• C. Manganese Acetate
• D. Potassium Permanganate

Answer 1

The correct option is B

Molybdenum Oxide

Explanation for the correct option :

Molybdenum Oxide $\left(\mathrm{MoO}\right)$ acts as a catalyst and catalyzes the conversion of propane $\left({\mathrm{C}}_3{\mathrm{H}}_8\right)$ to propanal $\left({\mathrm{C}}_2{\mathrm{H}}_5\mathrm{CHO}\right)$.

Explanation for the incorrect option:

Option (A) $\mathrm{Cu}/∆/$high pressure is used when Alcohol is converted to Aldehyde.

$\mathrm{R}-\mathrm{OH}\stackrel{\mathrm{Cu}/∆/300°}{\to }\mathrm{R}-\mathrm{CHO}$

Option (C) Magnesium acetate is not used in this conversion.

Option (D) Potassium permanganate is used for the conversion of Aldehyde $\left(\mathrm{R}-\mathrm{CHO}\right)$ to carboxylic acid $(\mathrm{R}-\mathrm{COOH})$.

$\mathrm{R}-\mathrm{CHO}\stackrel{{\mathrm{KMnO}}_4}{\to }\mathrm{R}-\mathrm{COOH}$

Therefore, the correct option is B.