Why is the potential inside a hollow spherical charged conductor, constant and has the same value as on its surface ?

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Solution

To move a test charge inside the conductor and on its surface, the work done is zero because the electric field intensity inside the hollow spherical charged conductor is zero.

So, the potential difference between any two points inside or on the surface of conductor is zero.

$V_{A} - V_{B} = 0$

$V_{A} = V_{B}$

$V_{A} - V_{B} = - \int E \cdot d l$

$V_{A} = V_{B} = c o n s t a n t$

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