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Question

Write half-reactions using electrons.

2MnO4+5C2O24+16H+10CO2+2Mn2++8H2O

A
Oxidation :C2O242CO2+2e ; Reduction :MnO4+8H++5eMn2++4H2O
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B
Oxidation :C2O242CO2+e ; Reduction :MnO4+8H++3eMn2++3H2O
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C
Oxidation :C2O242CO2+2e ; Reduction :MnO4+8H++7eMn3++8H2O
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D
Oxidation :C2O42CO2+e ; Reduction :MnO4+8H++eMn3++6H2O
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Solution

The correct option is A Oxidation :C2O242CO2+2e ; Reduction :MnO4+8H++5eMn2++4H2O
The balanced chemcial equation represents the oxidation of oxalate ions with permanganate ions.
2MnO4+5C2O24+16H+10CO2+2Mn2++8H2O
The oxidation half reaction is :C2O242CO2+2e.
It represents oxidation of oxalate ions to carbon dioxide.
The reduction half reaction is :MnO4+8H++5eMn2++4H2O.
It represents the reduction of permanganae ions to Mn(II) ions.

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