write IUPAC names of the following : 1. CH3 ----- CH2 ----- CH ===== CH2 2. CH3 ----- CH2 ----- CH2 ----- C ( CH3)2 ----CH3 3. CH3 ----- CH2 ----- CHO 4.CH3 ---- CH(OH) ---- CH3 5.CH3----- CH2 ----- CH2 ----- COOH

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$1 . {CH}_{3} - {CH}_{2} - CH = {CH}_{2} Numbering will begin from left . Number of carbon atoms = 4, functional group = double bond (- ene) So, IUPAC name is But - 1 - ene 2 . {CH}_{3} - {CH}_{2} - {CH}_{2} - C ({CH}_{3})_{2} - {CH}_{3} Numbering will begin from left . Number of carbon atoms = 5, substituent = 2 methyl groups at second carbon So, IUPAC name is 2, 2 - dimethylpentane 3 . {CH}_{3} - {CH}_{2} - CHO Numbering will begin from left . Number of carbon atoms = 3, functional group = aldehyde (- al) So, IUPAC name is Propan - 1 - al 4 . {CH}_{3} - CH (OH) - {CH}_{3} Numbering can be done from any side as the position of - OH is same from both sides . Number of carbon atoms = 3, functional group = alcohol (- ol) So, IUPAC name is Propan - 2 - ol 5 . {CH}_{3} - {CH}_{2} - {CH}_{2} - COOH Numbering will begin from left . Number of carbon atoms = 4, functional group = carboxylic acid (- oic acid) So, IUPAC name is Butan - 1 - oic acid$

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